{"id":712,"date":"2025-10-15T10:27:23","date_gmt":"2025-10-15T10:27:23","guid":{"rendered":"https:\/\/kapdec.com\/help\/?post_type=docs&#038;p=712"},"modified":"2026-04-10T10:58:53","modified_gmt":"2026-04-10T10:58:53","slug":"how-do-you-add-or-subtract-algebraic-terms","status":"publish","type":"post","link":"https:\/\/kapdec.com\/help\/how-do-you-add-or-subtract-algebraic-terms\/","title":{"rendered":"How Do You Add or Subtract Algebraic Terms?"},"content":{"rendered":"<p>Addition and Subtraction\u00a0of Algebraic Terms<\/p>\n<p><b>Addition in Algebra<\/b><\/p>\n<p>Let us understand this topic with an example.<\/p>\n<p>Mike\u00a0has 20 more chocolate candies than Steve. Then exactly how many chocolate candies does Mike have?<\/p>\n<p>We shall denote Steve\u2019s candies by the letter x. So \u201c<b>x<\/b>\u201d is a variable here. This can take any positive value. (because you can\u2019t physically negative number of chocolate candies)<\/p>\n<p>Using x, we can write\u00a0Mike\u2019s chocolates as x+20.<\/p>\n<p>The expression (x+20) is read as \u201cx plus 20\u201d.\u00a0Meaning\u00a020 added to x.<\/p>\n<p>If x is 10, then\u00a0Mike\u00a0would have 10+20= 30 chocolates.<\/p>\n<p>However\u00a0in this case, we do not know how many \u201cexact\u201d number of chocolates does Mike have, so we will say that the answer to above problem statement ends in a \u201cvariable\u201d form.<\/p>\n<p><b>Example:<\/b><\/p>\n<p>Elma\u00a0and\u00a0Mona\u00a0are sisters.\u00a0Mona\u00a0is younger than\u00a0Elma\u00a0by 4 years. When\u00a0Mona\u00a0=12 years,\u00a0Elma\u00a0is16 years. When\u00a0Mona\u00a0is 20 years,\u00a0Elma\u00a0is 24 years. We don\u2019t know\u00a0Mona\u2019s age exactly. It may have any value. Let \u201cx\u201d denote\u00a0Mona\u2019s age in years. Then how would you represent\u00a0Elma\u2019s age in an expression?<\/p>\n<p><b>Answer<\/b><\/p>\n<p><b>Mona\u2019s\u00a0<\/b>age = x years<\/p>\n<p><b>Elma\u00a0<\/b>is 4 years elders to Mona.<\/p>\n<p>So,\u00a0<b>Elma\u2019s\u00a0age<\/b>= X + 4<\/p>\n<p>&nbsp;<\/p>\n<p><b>Subtraction in Algebra<\/b><\/p>\n<p>Let us consider another\u00a0<b>example<\/b>\u00a0to understand the concept of\u00a0<b>subtraction<\/b>.<\/p>\n<p>Elma has made 10 donuts.\u00a0 However, Elma has distributed some\u00a0donuts\u00a0among guests. Then how much is\u00a0she left with?<\/p>\n<p>Let us denote the number of\u00a0donuts\u00a0distributed by\u00a0Elma as x. \u201cx\u201d is\u00a0a\u00a0variable which can take different values.<\/p>\n<p>Number of\u00a0donuts\u00a0made by\u00a0Elma\u00a0is 10.<\/p>\n<p>So the number of\u00a0Donuts Elma\u00a0is left with can be represented by an expression (10 &#8211; x). The expression is represented as \u201c10 minus x\u201d.<\/p>\n<p><b>Example:<\/b><\/p>\n<p>Apples are to be filled from\u00a0a\u00a0large box to another but\u00a0smaller box. When the\u00a0small box is filled completely, the large box is left with 15 apples. Then how many apples does small box has?<\/p>\n<p><b>Solution<\/b><\/p>\n<p>Let initially, the number of apples in large box = X<\/p>\n<p>When small box is filled completely, the large box is left with 15 apples.\u00a0Which means that we transferred \u201cX-15\u201d<\/p>\n<p>The number of apples in small box =\u00a0X\u00a0\u2013 15<\/p>\n<p>&nbsp;<\/p>\n<p>Multiplication and Division<\/p>\n<p>We can multiply a constant and a variable or two variables to get a product. It also leads to algebraic expression. Similarly, we can divide two algebraic terms to get a quotient. It is also an algebraic term. To multiply or divide two algebraic terms, first we multiply or divide the constants, then the variables and finally we write the constant and variable together.<\/p>\n<p><b>Example:<\/b><\/p>\n<p>Evaluate:\u00a0 4p \u00d7 2q<\/p>\n<p><b>Solution\u00a0<\/b><\/p>\n<p>= 4 \u00d7 p \u00d7 2 \u00d7 q<\/p>\n<p>= (4 \u00d7 2) \u00d7 (p \u00d7 q)<\/p>\n<p>= 8 \u00d7\u00a0pq<\/p>\n<p>= 8pq<\/p>\n<p>Here, 8 is the constant while p and q are the variables.<\/p>\n<p>&nbsp;<\/p>\n<p><b>Note:<\/b>\u00a030x and 30 + x are two different expression. In 30 x, x is multiplied by\u00a030. In (30+x), 30 is added to x.<\/p>\n<p>&nbsp;<\/p>\n<p><b>Example:<\/b><\/p>\n<p>Students went to buy pencils from a stationary shop. The price of one pencil is $ 3. Gigi wants to buy few pencils. Then how much money should she carry?<\/p>\n<p><b>Solution<\/b><\/p>\n<p>Let us say, or assume, Gigi\u00a0wants to buy\u00a0<b>\u201cx\u201d<\/b>\u00a0number of pencils.<\/p>\n<p>Since the price of each pencil is $ 3,<\/p>\n<p>Amount Gigi\u00a0should carry =\u00a0$\u00a0<b>3x<\/b><\/p>\n<p>Variable\u00a0<b>\u2018x\u2019<\/b>\u00a0is multiplied by\u00a0the unit price $<b>3<\/b>, (because 3 is constant)<\/p>\n<p>&nbsp;<\/p>\n<p><b>Example:<\/b><\/p>\n<p>4A \u00f7\u00a016\u00a0=??<\/p>\n<p><b>Solution<\/b><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-713\" src=\"https:\/\/kapdec.com\/help\/venture\/wp-content\/uploads\/2025\/10\/add.png\" alt=\"\" width=\"266\" height=\"150\" \/><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Addition and Subtraction\u00a0of Algebraic Terms Addition in Algebra Let us understand this topic with an example. Mike\u00a0has 20 more chocolate candies than Steve. Then exactly how many chocolate candies does Mike have? We shall denote Steve\u2019s candies by the letter x. So \u201cx\u201d is a variable here. This can take any positive value. (because you [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[591],"tags":[596],"class_list":["post-712","post","type-post","status-publish","format-standard","hentry","category-grade-6","tag-grade-6-mathematics"],"_links":{"self":[{"href":"https:\/\/kapdec.com\/help\/wp-json\/wp\/v2\/posts\/712","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/kapdec.com\/help\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/kapdec.com\/help\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/kapdec.com\/help\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/kapdec.com\/help\/wp-json\/wp\/v2\/comments?post=712"}],"version-history":[{"count":1,"href":"https:\/\/kapdec.com\/help\/wp-json\/wp\/v2\/posts\/712\/revisions"}],"predecessor-version":[{"id":1568,"href":"https:\/\/kapdec.com\/help\/wp-json\/wp\/v2\/posts\/712\/revisions\/1568"}],"wp:attachment":[{"href":"https:\/\/kapdec.com\/help\/wp-json\/wp\/v2\/media?parent=712"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/kapdec.com\/help\/wp-json\/wp\/v2\/categories?post=712"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/kapdec.com\/help\/wp-json\/wp\/v2\/tags?post=712"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}