{"id":10899,"date":"2026-11-02T02:04:39","date_gmt":"2026-11-02T02:04:39","guid":{"rendered":"https:\/\/kapdec.com\/help\/?p=10899"},"modified":"2026-11-02T02:04:39","modified_gmt":"2026-11-02T02:04:39","slug":"order-of-operations-bodmas-rule-pemdas-rule","status":"publish","type":"post","link":"https:\/\/kapdec.com\/help\/order-of-operations-bodmas-rule-pemdas-rule\/","title":{"rendered":"Order Of Operations: Bodmas Rule \/ Pemdas Rule"},"content":{"rendered":"
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KAPDEC® | Elite STEM Learning Platform | https:\/\/kapdec.com<\/a><\/p>\n

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Unit<\/strong>: Number System<\/h2>\n

Chapter<\/strong>: Order of Operations: BODMAS Rule \/ PEMDAS Rule<\/h3>\n

Reference<\/strong>: \u2013 Introduction to Order of Operations, Brackets\/Parentheses, Orders\/Exponents, Division and Multiplication (Left to Right), Addition and Subtraction (Left to Right), Mnemonics (BODMAS, PEMDAS, BIDMAS, BEDMAS), Worked Examples, Common Errors<\/em><\/p>\n

After studying this chapter, you should be able to understand:<\/p>\n

    \n
  • Introduction to Order of Operations & Its Need<\/li>\n
  • Brackets\/Parentheses & Grouping Symbols<\/li>\n
  • Orders\/Exponents (Powers and Roots)<\/li>\n
  • Division and Multiplication (Left-to-Right Rule)<\/li>\n
  • Addition and Subtraction (Left-to-Right Rule)<\/li>\n
  • BODMAS vs PEMDAS: Meaning and Equivalence<\/li>\n
  • Worked Examples & Common Mistakes<\/li>\n<\/ul>\n

    \nImportance of Brackets<\/strong><\/p>\n

    \u00a0<\/p>\n

    We have learnt till now that while solving any mathematical expression we follow a particular order i.e. the DMAS Rule.<\/strong> But the original rule further extends to BODMAS<\/strong> i.e.<\/p>\n

    \"\"<\/p>\n

    Source: Kapdec.com<\/p>\n<\/div>\n

    implying that while we solve any expression, we solve expression inside the brackets first followed by the rest. Let us learn more about brackets.<\/p>\n

    \u00a0<\/p>\n

    \u00a0<\/p>\n

    Using brackets<\/strong><\/p>\n

    Mathematical brackets are the symbols that are generally used to determine the order in which operations are to be done in any algebraic expression. Using brackets simplifies the operation in which there are multiple operators.<\/p>\n

    Using brackets in any expression implies preference should be given to the operation inside the bracket while solving, followed by other operations outside.<\/p>\n

    Example-<\/strong><\/p>\n

      \n
    • (9 + 6) \u00d7 14 = 15 \u00d7 14 = 210<\/li>\n
    • (18 \u00f7 3) \u00d7 (16 + 4) = 6 \u00d7 20 = 120<\/li>\n<\/ul>\n

      \u00a0<\/p>\n

      \u00a0<\/p>\n

      Expanding brackets<\/strong><\/p>\n

      Use of brackets allows us to follow our procedure systematically. Let us look at few examples on how we use brackets in various ways to expand and make our operations easier to solve!<\/p>\n

      \u00a0<\/p>\n

      Examples-<\/strong><\/p>\n

      (i) \u00a0\u00a0\u00a0\u00a0 5 \u00d7 105 = 5 \u00d7 (100 + 5) = 5 \u00d7 100 + 5 \u00d7 5 = 500 + 25 = 525<\/p>\n

      \u00a0<\/p>\n

      (ii) \u00a0\u00a0\u00a0\u00a0 107 \u00d7 109 = (100 + 7) \u00d7 (100 + 9) = (100 + 7) \u00d7 100 + (100 + 7) \u00d7 9<\/p>\n

      = 100 \u00d7 100 + 7 \u00d7 100 + 100 \u00d7 9 + 7 \u00d7 9<\/p>\n

      = 10,000 + 700 + 900 + 63 = 10,000 + 1600 + 63<\/p>\n

      = 11,663<\/p>\n

      \u00a0<\/p>\n

      (iii) \u00a0\u00a0\u00a0 14 \u00d7 106 = (10 + 4) \u00d7 106 = 10 \u00d7 106 + 4 \u00d7 106<\/p>\n

      = 10 \u00d7 (100 + 6) + 4 \u00d7 (100 + 6)<\/p>\n

      = 10 \u00d7 100 + 10 \u00d7 6 + 4 \u00d7 100 + 4 \u00d7 6<\/p>\n

      = 1000 + 60 + 400 + 24<\/p>\n

      = 1,484<\/p>\n

      \u00a0<\/p>\n

      With the help of above examples, we see that how using brackets can help us simplify our calculations by breaking any complex expression into simple ones and further defining the order in which it is to be solved.<\/p>\n

      \u00a0<\/p>\n

      \u00a0<\/p>\n

      Paradox \u2013 Can you solve it?<\/strong><\/p>\n

      #What is 6 \u00f7 2 (1 + 2)?<\/p>\n

      \u00a0<\/p>\n

      We know the first step would be solving the addition inside brackets, i.e.<\/p>\n

      6 \u00f7 2 (1 + 2)<\/p>\n

      =6 \u00f7 2(3)<\/p>\n

      But what now?<\/p>\n

      Is it<\/p>\n

      =6 \u00f7 (2 \u00d7 3) \u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 or \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 =6 \u00f7 2 \u00d7 3<\/p>\n

      =6 \u00f7 6\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 or\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 =3 \u00d7 3<\/p>\n

      = 1<\/strong> \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 or<\/strong> \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 =9<\/strong><\/p>\n

      \u00a0<\/p>\n

      The correct answer<\/strong> would be 9<\/strong> because after solving the operation inside of brackets<\/p>\n

      we open the bracket and then again follow the BODMAS rule.<\/p>\n

      <\/p>\n